Unix get specific line from file. txt sed -n means don't print each line by default.
Unix get specific line from file. txt starting from the line number 4.
Unix get specific line from file 2>At the END module for awk, it has gone to the end of the file, so you can not re-hold the line of the file So,my suggestion for you is: 1> try to remember all the desired rows in first awk 2>awk again -n tells perl to process the infile one line at a time passing each line to the commands specified in -e. How to extract specific lines from a file in bash? 0. txt +20 vi filename. ; It will just output text for Linux/Unix "LF" line terminators. Rows are straightforward enough the actual SO answer didn't work for me. head -n 15 file1. txt [+20] None of the above worked. Get specific line from text file using just shell script. csv which contain the following data: rabbit penguin goat giraffe emu ostrich I would like to count in the middle row individually I have a file where each line contains a sentence where one word is found between the character > and <. Search Forums. How to accomplish this?It may look something like: sed is the stream editor, in that you can use | (pipe) to send standard streams (STDIN and STDOUT specifically) through sed and alter them programmatically on the fly, making it a handy tool in the Unix philosophy tradition; but can edit files directly, too, using the -i parameter mentioned below. bak extension) use -i. One way is to have fixed-width lines in the file. Generally, I feel that it is nicer to do this with awk (if a little longer), because awk is better equipped to handle multiple Markup-based file types (e. 18 lines, line 45 becomes line 27) so you could run: To delete lines 2, 12-17 and line 57 from file data. Notice that without flags ls <FILE> and echo <FILE> are equivalent (for valid names of files in the current directory), so if you're using echo for that, you can use ls instead if you want. txt and results. Here are some examples: Head Command: The head command displays the first few lines of a file. These As others have shown you, there is no need to use cat -n. First get the highest value in the file into a variable. You learned to delete a particular line but what if you need to remove the last line? You may always get the total number of lines in a file using wc command and use this number with sed. head allows you to print the first X lines of a file, tail does the same but prints the end of the file. [A-Z0-9-] is Your first question as far as I know can be answered by coming at grep a different way. eg: 20080923 But before the date is other information, I need to read it from position 27. Code: cut -c2-5 i have a fixed-length record file where each column has a specific position. ; Mark the current position with command mM All, I know this is a very naive question but I could not find a way to get this working! I have a file with values like input. Hello cfaJohnson, I do apologise, but I had the code in origianally but becasue it was not working, I took it out and sent you the currently working version. For @user2232423 You should really read a tutorial on the Unix shell. Get specific line from unix command output. txt file with. Example. How can I read a file in cat << EOF > Hot Network Questions Why does an SSL handshake fail due to small MTU? You can use find to get the input files, tail to get the end of the files, and sort to sort them. The full code is below: Hi, I have below type of data in a text file in unix. I want to read one part of one line from a file. You can have multiple commands, specifying several -e options. Use -i to ignore case (so you also match "Happy", "HAPPY", etc) and a space before to match only "happy" and not any other words that contain that sequence of letters. txt file: # here are some text # please do not edit these lines # blah blah. sed receives its arguments on the command line (-e and "${firstline},${lastline}p;${lastline}q" are arguments). Zip is available in many operating systems like The simplest way might be to use source or simply . zip {. sed -i 18r<(sed '16,80!d' file1) file2 Where <(sed '16,80!d' file1) is substituted with the name of a pipe from which the output of sed '16,80!d' file1 can be read. I know that this is after a given line number which I know. Is it something similar to?: more +/"string" file_name Thanks (4 Replies) Discussion started by: aku. aNumber timestamp commandInformation I use the command . To get a specific line from a file I have one file that has more than 100k+ records. Chaining these all together, you would get something like: Also please help how can i get number of lines | The UNIX and Linux Forums. txt using sed you could do something like this: sed -e '2d;12,17d;57d' data. how to read a line Extracting specific text from a text file in UNIX. Conclusion. For example: Martin went shopping at >Wallmart< and lost his wallet French food >tastes< great I am looking for a command to run from the shell that will print the word inside ">" and "<" for every line. Faster and easier tools exist for the same purpose @fedorqui 1)no piping! 2)Use regular expressions 3)Get line numbers, file name with relative path Remove the last line using sed. To help visualize it, this is what it would look like if we wanted to add blank spaces around $2 instead of quotation marks: '{print " "$2" "}'. How do I cat a file piped from echo? 72. You can translate the first colon produced by grep and all other whitespace to a single space with sed 's/:/ /;s/\s\s*/ /g'. txt However, it prints the line number in a separate line above the real line. What unix shell command can I use to get lines x (e. -e means execute the next argument as a sed script. To display the 15th line from a file using awk, use this command: awk "NR==15{print;exit}" <filename> For lines 15 to 25, use this command: awk Try file -k. Use tail to get the contents of the file from line 51 onwards, and then grep that. I keep getting references to Tail and Head, and I know how these work, but i'm Quick UNIX command to display specific lines in the middle of a file from/to specific I have a problem reading a string in specific line and specific position. For example: POP3_SERVER_NAME = localhost. I have some text file (for example json). How do I delete this line from the file @Timo The quotes and backslashes breakdown can be envisioned as "\"" + $2 + "\"". list|awk '{print $1}'` Then grep the file using that value. stdin);print # jsonv get the json object value for a specific attribute # first parameter is the json document # second parameter is the attribute which value should be returned get_json_attribute This is using standard Unix tools available on most distributions. We then pipe the output from the first step into the tail command to retrieve the last entry: head -n X Doing this with sed requires some additional shell trickery. Very interesting to be used when you know what line you want. Only the tail/head version begins to get a little faster as the line approaches the end of the file. You can get around this with a construct such as: I want to copy lines 10 to 15 of a file into another file in Unix. I have a sorted, delimited type file and I want to extract a specific field in specific line. Tried both vi filename. Looping over the first file, while NR (record number) is equal to FNR (file record number) using the next statement stores all the line numbers in the array. Whats the exact syntax if i have file as Noname. stop_id,stop_code,stop_name,stop_desc,stop_lat,stop_lon,location_type,parent_station,zone_id I have a csv file which contains a large number of entries. To pass in the line number as an argument, double-quote the expression, e. txt I want to read one part of one line from a file. This I have a huge file on my unix server from which I need to extract certain parts. 1 deiauk David Smith from California 12 58 2 edvin from Nevada 12 5 8 95 2 48 5 3 jaco My Name Is Jacob I'm from NY 5 6 845 156 585 4 from Miami And I need to get values after specific word from is it possible to do that Lastly, you can use awk command to print a specific line from a file. tail -n +51 filename. csv From the man page:-n, --lines=N output the last N lines, instead of the last 10 If the first character of N (the number of bytes or lines) is a '+', print beginning with the Nth item from the start of each file, other- wise, print the last N items in the file. Its use is to print a file to standard output, which means we can use greps standard input interface to read data in, rather than having to learn what switch to apply to grep, and sed, and awk, and pandoc, and ffmpeg etc. txt Each line in the file has a unique ID, and I have a specific list of IDs (that are not consecutive) that I wish to What unix command to extract line from specific string to another specific string. Guess that would be due to my use case of extracting text from specific column range and paste it to text A simple sed substitute will also work given the line number, e. grep -o '[^ ]*entry[^ ]*' That will print only words containing the string entry no matter where they are in file or what comes before or after them. Besides grep, you can also use other utilities such as awk or sed. Improve this question. ) Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company How do I get a specific line of a file using 'cat' command? 0. Ask Question Asked 4 years ago. . txt Where /path/to/ is the path to your files, file*. Another way is to loop, reading lines one a time until you get to the line that you want. Sign up or log in to customize your list. For example, if you are looking for second columns that contains abc: awk '$2 ~ /abc/' The "g" after the final slash means to do it "globally", ie: over the entire file rather than on only the first match it finds. txt | tail -11 or . This text is on the third line. Here is a few examples. seek to a line in a file and display it on linux. For example: POP3_SERVER_NAME = localhost I want to return only localhost, using sed. txt you can use the -i option which means to edit the file "in place". Redirect the output to a new file if you wish to save it Judging by the format of your input file, you can get away with delimiting on -instead of spaces: awk 'BEGIN{FS="-"} {print $2}' filename FS stands for Field Separator, just think of it as the delimiter for input. txt | tail -n 6 > file2. The best command line collection on the internet, submit yours and save your favorites. So I would like to know the line number of the first "total" after the line X. total 16078 drwxr-xr-x 33 root wheel 1. Create a sample file say testfile1 in our case. The portion before and after the match will consistently vary. sed -n -e '10,100p' input. I know how to do simple grep on a file. Follow If you want the text file line by line including blank lines and terminating lines without CR, while read line in a file from a specific column. Thanks in advance. They can also be used to display a specific line from a file. It's a kind of reverse of what I can get in grep with -A and -B to print matching lines as well as lines before/after the matched line. tmp && mv file. For example: grep. txt awk In this post, we will look how to get a specific line or a range of lines’ output from a file in linux. e. Each file is stored in a single . You're conflating two distinct concepts (arguments and redirection). Linux and Unix Man Pages. finding line number of file using grep command Linux. txt is the pattern of your file names, -type f finds only files, not directories, -n1 tells to tail to return 1 line, and output. Use head and tail to cut the file and to get only the range you need before redirecting the output to a file. After that when FNR of the second file is present in the array (true) the line is printed (which is the default Hi, I have a huge file & I want to add a specific text in column. sed -i '2s/^/# /' file The above will edit file in place commenting line 2 inserting "# "at the beginning of the line. Short version: file -k somefile. The $= signifies the last line of the file. To explain: FNR==NR will occur only when reading file_with_linenr, not file. on that line I want to replace the string "0," with "1,". Read content of file line by line in unix using 'line' 1. bak with the command. To get an overall number of lines in the file, use: sed -n '$=' example. Forum Home. Here is an example to extract columns by name from a file test. I'm trying to modify a line in my_course that starts with "123". #!/bin/bash sed -i "$1s/^/# /" "$2" Will take the line number as the first argument and the file to comment as the So pulling open a file with cat and then using grep to get matching lines only gets me so far when I am working with the particular log set that I am dealing with. As you can see, the positional arguments (i. grep "^May 1\b" file Or: sed -n '/^May 1\>/p' file Or: awk '/^May 1\>/' file The above two assume a tool, such as the GNU awk or sed, that supports \> as a word boundary regex. load(sys. I have an input file that has a fixed position and fixed length for each value in every row. txt), this file contains some lines and for example one line is: abcd=11 But it can be for example: abcd=12 Number is different but abcd= is the same in all case, so could anybody give me command for finding this line and remove it? I want to grep certain lines by keyword and redirect the output to specific line number of an existing file. log:. Meaning, you don't need to create a second file to contain your result. txt I need something that will find the line containing a specified category which will then extract the complete line and move it to a new text file (preferably named after that category). file Value1 Value2 server1/mylogin,mypasswd Value3 Value4 And in my code, I am reading the file line by line and processing it. The -a tells perl to expand each line around the field separator (this defaults to space), and assign this to an array called @F . However, since we piped the tail command’s output to grep, the line numbers reported by the grep command are not the actual line I would like to run a command in a shell script for ex ls -al and I need to extract the 3rd word of the 5th line. Each field has its trailing comma removed (if one exists) before it's printed on its own line. txt file: stack ping dns ip remote Results. How to read specific line of files with a Linux command or Shell Script. What is a good command to print the middle of a file? something like middle --start 10000000 --count 20 (print the 10’000’000th till th 10’000’010th lines). 1. You can probably still get a hold of GNU grep older than this functionality. Command grep "key" temp_file >> desired. join <(sort padded_line_numbers) <(nl -w 12 -n rz data) | As pointed out by Max, you can't, but checking files modified or accessed is not all that hard. Caveat before someone points out the obvious: this will only work for something like 99% of grep executables out there. join. txt Please help I get ` File "<string>", line 1 import json,sys;obj=json. csv However, there's also csvtool, and probably a number of other csv bash tools out there:. Easy with perl! If you want to get line 1, 3 and 5 from a file, say /etc/passwd: perl -e 'while(<>){if(++$l~~[1,3,5]){print}}' < /etc/passwd There are many ways to do this. Finally, instead of < input. I want to add text "Hello" (2 Replies) The second response is a bit obfuscated. For example: find /path/to/ -name "file*. mdc. Learn how to extract specific lines from a file by line numbers using sed and awk. It may delete them on BSD too. Let say you want to search for a string is in the file named GPL. txt, we can use the following command − In fact this is not true: tail | head is about as efficient as you can get in terms of file I/O. I have a file containing the following lines: If input changes, and before name parameter you will get new-line character instead of space it will fail some day producing unexpected results. As we can see, this time, the command has printed the line numbers of matched lines. For this I got the shell script as Suppose I have a file which is getting appended in every seconds/minutes. Suppose if my file name is abc. The We first use the head command to get lines 1 through X from our input file. how can retrive two or more column based on their positions in I have a log file which contain lots of line like below: 2017-07-16 01:06:07 Unix & Linux Meta your communities . The only way you can count the lines is to look for the new line characters in the file, and this means you're going to have to read each byte. I do this to extract the line: sed -n '3p' installation. At first time I have read whole file and stored the last line number(eg: last_line_numer was : 2000) later I want to read file using 'grep' command to look for a pattern from line number 2001 to end of file. What is Linux order, which I can use to read some general lines somewhere in file? For example from the line 500 to the line 700. Other programs will do it for you. txt, assuming there are 5 lines in data. I'm trying to select a specific line from a file and replace a string on that line with another string. The <${filename} tells the shell to connect the file whose name is in the shell variable filename to the stdin of the sed process. – @Jacob It's not useless use of cat at all. The -n option is used to specify the number of lines that should be displayed. txt" -type f -exec tail -n1 {} \; | sort --numeric-sort --output output. cat foo. Then read the appropriate amount of data based upon the line number you want and the number of bytes per line. It could be necessary to set the EOL to an unused character or to linefeed (default is ; I guess everyone knows the useful Linux cmd line utilities head and tail. 1>the NR has gone to the last line. Even if the numbers at the beginning of each line aren't actually there and you only included them for descriptive purposes, it will return what is wanted. awk 'NR == FNR {nums[$1]; next} FNR in nums' numberfile datafile simply referring to an array subscript creates the entry. 12 I want to cut the first 20 lines from ADDRESS_FILE and put that into a new file then cut the next 40 lines from ADDRESS_FILE so on Display specific columns of a file in Linux - Overview We often perform various file operations on our Linux systems. Then the output is saved into output. 0fx12923a I have another file with a list of numbers it looks like this (NUMBERS_FILE) 20 40 . Print only the lines in the range and redirect it to the output file. txt > file2. I have to read certain lines from the file. This works even, if there are empty lines before the nth line. extract specific line from a file using awk. To extract lines that start with May 1:. txt For a variable line number: sed -i "${line}d" file. The surrounding quotation marks are indicating something to be appended to the output, and the escaped quotation mark (\") is being printed. Today's I have a collection of text files containing more data than I need. grep -A10000 KEYWORD file Where 10000 is just a big number to denoted the amount of lines until the end of the file, which for your practical daily use should be enough. txt to be written to stdout (bat bat bat). head -c12 file. Display specific lines using head and tail commands. In a Unix shell, how can I pick a single line from a text file by its line number? Say I want whatever is at line 3 in animals. Thanks in advance! JMA Not exact answer but may be useful for anyone who does some manual log file investigations and wants to extract huge range of lines without much effort and line calculation, especially when tail -f is involved. I have this file. The problem is pretty straightforward. For example, line 8000 would be gotten like this: command -line 8000 > output_line_8000. Can anyone help? What I currently have is: str = $(ls -al foo | cut -d" " -f3) This is storing all the words in 3rd field, but I am unable to get the word from 5th line. If you want to precede the line number in the same line of the actual line, you can pipe nl to sed, nl file. Reading specific line in a text file. The \K in PCREs causes whatever was matched up to that point to be discarded (and therefore not printed, because of -o). txt What unix command to extract line from specific string to another specific string. Didn't get what you said. Modified 5 years, Custom Iterator for Processing Large Files Make numbers 1-100 using 2,0,2,5 I need to remove a specific line number from a file using a bash script. The format of the line is. txt will tell you line terminators: It will output with CRLF line terminators for DOS/Windows line terminators. drwxr-xr-x 33 root On my system, your last example is generally faster than the awk, head/tail or ruby versions unless the line is near the end of the file. bin>output If I wanted to extract 12 bytes from byte61 I could do something like. bin|tail I think the easiest is using csvkit:. Here, we’ll cover the different methods for achieving this. txt): Alligatoah A couple of other techniques to get the first word of the 3rd line: awk -v line=3 'NR == line simple, robust, efficient, easily maintainable and extensible and will work using any awk in any shell on every Unix box (unlike every sed answer posted so far which all I am working on a script which should extract specific kind of users and its corresponding uidNumber from a command result and output it into a file. Example: To find all files modified on the 7th of June, 2007: Hi, In need to see a specific line in a file , I work in tcsh sell, some kind of cat -line <XXX> templet_file Thanks, Ziv | The UNIX and Linux Forums. ). Here's what you'll see: I want to extract an exact line from a very big file. txt head/tail combination. Thus when reading from file, only the (FNR in a) case applies, and prints the text of the relevant line if its number was put in a in parsing Somewhere in the middle of my CSV file is this line: Products below this line are out of stockNumber, month, year, reference, store Note:Number, month, year, reference and store are the CSV fields. Skip to main content. highest=`tail -1 file. Considering the file is already sorted, pickup the last line in the file. "1p" is a first command. Let’s get a more clear picture through an example. Preferably in sed, awk or other tool that's available in MinGW32. | The UNIX and Linux Forums. list Hi, What is the command i can use iof i want to display a particular line from a file, i have the line number with me. How do I extract lines out of a text file using bash in linux? 150. log | grep CMDTYPE=NEW to filter out certain lines that I want. How would I access that word, without knowing in advance the word I am looking for? If I know a specific word or string is in the third column of text in a five column text line, how can I take the word in the third column? I'm using the bourne shell. I would like to extract specific lines from a file and output them into another file. txt to file2. csv efevfe,132143,27092011080210,howdy,hoodie adfasdfs,14321,27092011 I use this. txt and file2. Gets the 2nd column: csvcut -c 2 file. I am having files file1. txt starting from the line number 4. If, however, you really need to parse the output of cat -n and show only specific lines (for example, 4-8, 12 and 42), you could do: $ cat -n file | awk '$1>=4 && $1<=8 || $1==12 || $1==42' 4 Line 4 5 Line 5 6 Line 6 7 Line 7 8 Line 8 12 Line 12 42 Line 42 There are many ways to do this. to_Hari to_kumar Can anyone help me? The sed command with the options -n and $= can count and display the total number of lines in the file. In this case, the text of the line is added to a set a, and execution skips to the next line of input. . Search I am trying to display contains of a file from a specific line to a specific line(let say, from line number 3 to line number 5). sed -n '10,15p' file1. The essence of which is to use -newerXY and ! -newerXY:. Introduction to the Problem. I want to return only localhost, using sed. One of the most common operations is to display certain columns from a text document. It saves time because we don't have to learn a new switch every time we want to do the same It can also be used to remove the first line of a text file by using the -n option. To split the rest of the file you could use a FOR /F loop. This would work with your example, because there are no spaces in the variable values. csv: Trying to read from specific fields of a CSV file. Otherwise you could use the amount of lines in the file as parameter like this. I know how to tail a text file with a specific number of lines, tail -n50 /this/is/my. I need to remove some records from my file based on some specific position Like If 'AB123 ' is present in position 38 to 45 than that line should be removed from file before starting the sql loader. And I want to copy the word "is" from that sentence into a variable. Sed utility works on each line individually, running specified commands on each of them. We will look at these options step by step. I would like however to remove those lines and the line directly after it. I only want the part timestamp and the last 9 characters from the line to be returned, not the Yet the 'newfilenameY' file and the original file 'filenameX' both still contain the line that I'm trying to delete. How to extract a specific text of an Here are an alternative method and a bit of benchmarking, adding to that in Weijun Zhou's answer. txt file based on a combination of the following three requirements:. user@box:~$ grep -C 2 my_regex out line 3 line 4 line 5 my_regex line 6 line 7 user@box:~$ Reference: manpage grep-A num --after-context=num Print num lines of trailing context after matching lines. The line number is stored in a variable called lineno. Is there a quicker way of getting a couple of column of values than futzing with sed and awk?. I had an idea that if I could grab 1000 record hunks of the file, and pipe the records out, that I could perform a loop until I got to the end and process 1000 records at a time. log However, how do I make that line count a variable? Let's say I have a large log file which is appended to daily by some program, all lines in the log file start with a datetime in this format: Day Mon YY HH:MM:SS find is the standard tool for searching files - combined with grep when looking for specific text - on Unix-like platforms. saket@ngelinux$ cat testfile1 first second third fourth fifth saket@ngelinux$ 1. The syntax is as follows for bash, ksh, zsh, and all other shells to read a file line by line 2. when we want to read from a file. grep LATENCY file. It ensures that only the line number is printed to the standard output. To be more specific: lets say my file has 1000 lines & 4 Columns. datatxt="Line 1 without colon I want this:the part before the colon nope, not me other line with colon:that can be found" Your command shows the first field of all lines I have very large genotype files that are basically impossible to open in R, so I am trying to extract the rows and columns of interest using linux command line. sed -n '10,20{=;p}' file. txt sed -n means don't print each line by default. txt p in above command stands for printing. To remove the first line of a text file called file. sed -i -e 's/few/asd/g' hello. For example: I want the strings from lines that start with hello: hi to_RAm hello to_Hari hello to_kumar bye to_lilly output should be. File systems don't track line numbers within files. Or you could symlink grep to echo and have a laugh. 2. Like I said I'm new to unix so maybe I've gotten the sed command wrong you can use cat -n to display the line numbers and then use awk to get the line number after a grep in order to unix command to read line from a file by passing Bash Script to Find Line Number of String in File. grep -oP 'BIG\*20021208\*00001\**\K[A-Z0-9-]+' file Explanation. zip -'s/. Tabulator is a set of unix command line tools to work with csv files that have header lines. txt > output. zip-filename} file with the extension . Output lines 2, 4, and 7; Line numbers from 10 to 20: Print if the line number is even; Line number > 20: Skip Therefore, the expected output looks like the following: how do I extract 12byte chunks from a binary file at certain positions within the file. It need a way to match lines to a pattern, but only to return the portion of the line after the match. I want to copy lines 10 to 15 from file1. But I want to add this text from a specific line number to a specific line number & another text in to another range of line numbers. Understanding the Scenario I am reading a file that contains over 5000 lines and I want to assign it to a shell variable array (which has a restriction of 1024 rows). On the first line of the files to be read is a date but in numeric form. Your sample file $ cat -n GPL 1 The GNU General Public License is a free, copyleft license for 2 The licenses for most software and other practical works are designed 3 the GNU General Public License is intended to guarantee your To get the file from the nth line you could use more +n (For line1 is n=0). Try less the-big-log-file. I have a text file, and I want extract the string from each line coming after "OS=" input file line A0A0A9PBI3_ARUDO Uncharacterized protein OS=Arundo donax OX=35708 PE=4 SV=1 K3Y356_SETIT ATP-dep To ensure we discuss the most frequently encountered scenarios, let’s extract lines from the input. The sample command result is: dn: unix bash - extract a line from file. I'm looking for something that will deal with Your first question as far as I know can be answered by coming at grep a different way. ; It will output with CR line terminators for MAC line terminators. txt to create a backup of the original file (with a . sed -i 's/[ \t]*$//' "$1" Be aware the expression will delete trailing t's on OSX (you can use gsed to avoid this problem). Could any one please help me . Display Single Column Let's create a new folder for our example. Save a cat! Unfortunately, unless you can guarantee that every line in the file is the exact same length, you're going to have to read through the whole file, or at least up to the line you're after. When such a line is found, it iterates over the whitespace-delimited fields of that line, from the second field onwards. grep -i "hello" abc. Use sed:. The input. getting a column of a specific line in bash. $1, $2 and $3) are returned because that is what is in the script. Viewed 190 times 0 lets Getting specific lines of a file. txt sed has the = command that prints the line number. get a specific line from in linux using grep. txt | user@box:~$ grep -B 2 my_regex out line 3 line 4 line 5 my_regex user@box:~$ Grep exact matching lines and 2 lines before and after. json get me 100 first lines back. Ask Question Asked 5 years, 9 months ago. If the situation is reversed, so that you have the full path and An alternative might be grep in combination with the -A flag, e. Assuming bash, you could use. If you know the line numebrs, say you want to get line 1, 3 and 5 from a file, say /etc/passwd: perl -e 'while(<>){if(++$l~~[1,3,5]){print}}' < /etc/passwd Share In this article, we’ve addressed different ways to read a specific line from an input file. For example: If I search for "<b >CategoryOne</b >" then I need it to move every line containing "<b >CategoryOne</b >" to text file categoryone. First, consider the minimum amount of work necessary: to find the X'th line in a file, the only general way to do it is to read every byte and stop when you count X newline symbols as there is no way to divine the file offset of the X'th line. This is my favorite way If for example you want to get the lines 10 to 20 of a file you can use each of these two methods: head -n 20 york. sed -n '10,20p' york. Meaning line 1 position 27, I need to get that number and see if it’s greater then another number. You can also run BSD or other grep implementations which use different command line flags. I tried piping the output into the cut command but it does not accept string delimiters. 203. Search Community Posts. The DareDevil of the Unix commands, dd to the rescue! How can I open a file with line numbers displayed from the command line in 'vi'? 41. txt, I want to copy all these lines and paste them in file results. for example: 1 aaaaaa bbbcb cccccc 2 grep --no-filename "^kgf" *. Given that we are now delimiting on -, your 7th field before now becomes the 2nd field. sudo apt-get install csvtool (for Debian-based systems). I cannot use sed for a variety of reasons, least of which is that it is not installed on all the systems this script needs to Is there any bash command that will let you get the nth line of STDOUT? That is to say, Read words in a specific line in a text file using shell script. We can prepend each command with a range parameter that specifies if this command should be applied to specific line or not. You can get around this with a construct such as: Your command is actually working as expected; you are asking sed to return lines 4 and 5 from the file "2input1output". An easy way to showcase the capabilities of shell scripting is to create a Bash script that prints a specific line from a file. unix; io; sh; Share. 4 Replies. You then want the first and third section, which can be achieved with cut -d ' ' -f 2 --complement. 2K Aug 13 16:57 . monkey monkey monkey cat cat cat bat bat bat horse horse horse Is there a standard program or simple way to do this? I'm trying to figure out how to display a certain line in a text file. TXT and i want the cursor at line 100 while opening in VI through UNIX Prompt? This uses awk to look for any line that starts with the string Members. Function that extracts certain specified line of a text file in Unix. I have one file (for example: test. This is my input file: somefile. Here is a sample below: Data. Modified 4 years ago. Assuming you have a data file you want to extract rows from and a line_numbers file that lists the numbers of the rows you want to extract, if the sorting order of the output is not important you can use:. The -o makes grep print only the matched portion of a line and the -P activates Perl Compatible Regular Expression (PCRE) syntax. grep -A$(wc -l file | cut -d' ' -f1) KEYWORD file Enter the line number you want to print: 3; If the file exists and the line number is valid, the script will output the specified line. zip. Open the file, go to starting position (e. Is there a specific word for the poetic technique of using a single word to load emotions onto an object? So say i have a file with content on each lines, know the number of lines in advance and want to know the content of specific lines, i can do: awk 'NR==10' file But while i already know one way (u Skip to main content I will simulate the data. In bash script how do I reference a file as the input for an interactive prompt. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog Using GNU grep iwth the -o option to return only the matched string:. g. tmp file. I've researched other questions on here, but haven't really found one that works for me. Bash - View a specific line in a file with I am trying to get the number value from this string variable and then store it in another variable. txt f To delete line 5, do: sed -i '5d' file. txt What I need is that I can append the There is no need for the redirection with sort and what's the point of piping to uniq when you could just do sort -u file -o file what you're doing is removing the duplicate values i. I'm looking for a way to efficiently extract a byte range from a large log file. 3. I get the line number from the grep command with the -n option. 10,100p is a sed script that means starting on line 10, until line 100 (inclusive), print (p) that line. which command can be used or any This reads byte position 2-5 on every line of a file. From unix script i want to read string value in a file from position 2 to 5. I have a requirement to go to particular line in the file and from there read the contents till it meets a particular criteria. The purpose of the word boundary is to prevent the regex from matching, for example, May 10. For instance, if I have the output of ls -hal / and I want to just get the file and directory names and sizes, how can I easily and quickly doing that, without having to spend several minutes tweaking my command. Linux How do I replace a specific line of a file with different text, and then save that file to its original name? I believe I want to use If you want to restore the file's metadata from the archive, be able to restore files of any type (including symlinks) and with arbitrary names, and also choose the new name of the file, you could use libarchive's bsdtar (which also supports ZIP format archives) instead of unzip as: bsdtar -nqvvxpf file. You can use the in place option -i of sed for Linux and Unix:. Further, we’ve discussed how to optimize the Bash, sed, and awk solutions to gain better performance. It's a fastq file, though I don't see how that would make any difference. #! /bin/ksh (6 Replies) I have a file with a list of address it looks like this (ADDRESS_FILE) 0xf012134 0xf932193 . txt > file. In shell, print only the specific line/word from command's output. I know AWK or grep are powerful enough to do this in one line, but I couldn't find an example that could help me do it on my own. More In general, I will have few words which I need to grep on my big log file and print out the line which contains those words. If I wanted to extract the first 12 bytes I could do something like. ZIP is a compression and file packaging utility for Unix. txt. Use AWK with delimiter to print specific columns. sh How do I extract only the localhost part? Hi all, I'm looking for the line number where the string "total" appears. Then parse out the number using awk. For example: head -n 100 file. Is it possible to use grep a file from a sed -n 5p <file> - (To print a specific line from a file You can get one specific line during any procedure. log and I need to find a line which contains word "hello" then I always do it like this and it prints out the line for me. Unix file read from specific position onwards. Get a specific words from a specific line from a text file in NetBSD. this is the 4th line that data should go on. The UNIX and Linux Forums. log I have two files data. Each file's first line contains a comma-separated string that looks like this:. 4 Dear UNIX community, I would like to to count characters from a specific row and have them displayed line-by-line. If you don't have gsed, here is the correct (but hard-to-read) sed syntax on OSX: To print the columns with a specific string, you use the // search pattern. I wrote a tutorial about this, as late as today. I have following File (wishlist. to 15) from a file. txt | sed -n '10,20p' You may want to set some nl flags to make the output better. txt If the -i option isn't available in your flavor of sed, you can emulate it with a temp file: sed "${line}d" file. */newname/S' some/dir/originalname I want to extract the string from a line which starts with a specific pattern from a file in shell script. Each line in the file has a unique ID, and I have a specific list of IDs (that are not consecutive) that I wish to extract. I have a file called testAwk2. I can use head order for the reading of the first lines. grep doesn't seem to help and except doing a for loop I can't think of anything else. Consider the following:. The find command is often combined with xargs, by the way. Otherwise you need to use grep + cut or awk, as stated in other answers. e your fileb contains 1,2,3,5,7 the OP wants the unique lines only which is 2,3 and is achieved by uniq -u file File extension has nothing to with it, your answer is wrong. If you want to keep the original file intact and write to another file you can pass the new file name to the write subcommand: ed -s in_file <<IN 78,86d 65d 51d 20,37d w out_file q IN 1 Unless you are willing to calculate the new line numbers after each d elete, which is quite trivial for this particular case (after deleting lines 20-37, i. In this tutorial, we’ll explore various command-line utilities to show characters at specific positions in a file. If your file is longer than suggested, this version (suggested in the comments) will tail -n +2 file. Syntax: Read file line by line on a Bash Unix & Linux shell: 1. 10) to y (e. By specifying -1, we can remove the first line of a text file. to read and execute the file. grep -n will print line numbers with the match. I need to open that file, look for the word "MdcFile" and get the string that follows between quotes, which would be BILA_CO_PM_MKT_BR_CUBE. with /2021-11-21 19:00 search). It uses p command which normally prints all However, I wish to extract just the name (ie "john") from each line instead of the whole line returned by grep. Zip is used to compress files to reduce file size and is also used as a file package utility. So I have a file named my_course. When you send it a list of files (or directory to recurse through with -r or -R), it will always output which file it has found a match in as well as the line number. 0. txt | sed '/bar/d' to remove lines containing the string bar in the file. grep "^${highest} " file. In that case, it's often the most reasonable approach to remove those lines, put into the file what you want to be added and then re-add those lines, because putting the lines in between straight away can be much more effort, and goes against the potential desire to In this quick tutorial, we’ll have a look at different approaches to read a specific line from a file. XML or JSON) require specific lines at the end in order to be valid files. Showing a character at a specific position in a file in Linux can be useful in various situations, particularly when we need to manipulate or extract specific data from a file. head -c72 file. (So if it does not explicitly mention any kind of line terminators then this means: "LF line terminators". anhvbrocmlfllmmjexbkxhwxhjgtaikfvgntdikadnamasclcdwdpube